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How to get a differential gain > 40V/V?
How to get a differential gain > 40V/V with a diferential pair with PMOS input stage and resistive loads with Vdd=2.5V, Vss=-2.5V and Vo=0V by changing any value of bias current, transistor size and resistance?
Differential Amplifier with Resistive Loads
* Set options
.option post probe
* Element Statements
vddvdd02.5
vssvss0-2.5
m1vout-vin+1vsscmosnw=100ul=1.0u
m2vout+vin-1vsscmosnw=100ul=1.0u
r1vddvout-50k
r2vddvout+50k
i11vss100u
e1vin+23vss0.5
e2vin-23vss-0.5
vcm2vss2.5
vs3vssdc=0
* Control statements
.dcvs-0.50.50.01
.probev(vout+,vout-)
.tfv(vout+,vout-)vs
.op
* Include device model with filename "cmos05.mod"
.include cmos05.mod
.end
Since you're not going to change the transconductance of the devices about the only thing you -can- to is increase the load impedance (since load impedance times transconductance equals stage gain). And you'll also have to increase the supply voltage(s) to keep the currents the same (because the transconductance is a function of source-drain current).
Doug
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