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The work function for metallic rubidium?
The work function for metallic rubidium is 2.09 eV. What is
the minimum frequency of light required to observe the photoelectric
effect? Calculate the kinetic energy and the speed of
the electrons ejected by light of wavelength 195 nm.
At the threshold frequency the energy of the light wave equals to the work required for electron emission:
h · f₀ = W
(h Planck's constant)
=>
f₀ = W / h
= 2.09eV / 4.135667×10^-15eVs
= 5.054×10^14s^-1
The kinetic energy of the electrons emitted at higher frequencies are:
E = h·f - W
= h·c/λ - W
(c speed of light)
= 4.135667×10^-15eVs · 2.99792×10^8m/s / 195×10^-9m - 2.09eV
= 4.27eV
= 6.838×10^-19J
E = m·v²/2
=>
v = √(2E/m)
= √(2 · 6.838×10^-19J / 9.10938×10^-31kg)
= 8.66×10^5m/s
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