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polynomial question. write these P(x)=2x^3 -17x^2 +90x -41 into linear factors; where 1/2 is a zero?
write P(x) as a product of linear factors
please help me because i'm stuck in the middle..
my answer (which half way stuck)
P(x)=2x^3 -17x^2 +90x -41
P(x)=(x- 1/2) Q(x)
P(x)=(x- 1/2) (2x^2 -16x^ +82)
P(x)=(x- 1/2) ??
thk for helping me 
Double the factor x - 1/2 to get 2x - 1 then divide 2x - 1 into P(x) to get (2x - 1)(x^2 - 8x + 41)
Now since x^2 - 8x + 41 is not factoable using integer coefficients solve x^2 - 8x + 41 = 0:
x = (8 +- sqrt(64 -164) ) / 2 = 4 +- 5i
So the factorization is (2x - 1)(x - 4 - 5i)(x - 4 + 5i).
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